Base | Representation |
---|---|
bin | 10101100011011111… |
… | …111001010011001111 |
3 | 2012201221210020021121 |
4 | 111203133321103033 |
5 | 334344400021111 |
6 | 14344323141411 |
7 | 1446350650513 |
oct | 254337712317 |
9 | 65657706247 |
10 | 23144142031 |
11 | 98a72a050a |
12 | 459ab14867 |
13 | 224abb98ca |
14 | 1197ad0143 |
15 | 906cd3871 |
hex | 5637f94cf |
23144142031 has 2 divisors, whose sum is σ = 23144142032. Its totient is φ = 23144142030.
The previous prime is 23144142011. The next prime is 23144142089. The reversal of 23144142031 is 13024144132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23144142031 - 27 = 23144141903 is a prime.
It is a super-2 number, since 2×231441420312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 23144141987 and 23144142005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23144142011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11572071015 + 11572071016.
It is an arithmetic number, because the mean of its divisors is an integer number (11572071016).
Almost surely, 223144142031 is an apocalyptic number.
23144142031 is a deficient number, since it is larger than the sum of its proper divisors (1).
23144142031 is an equidigital number, since it uses as much as digits as its factorization.
23144142031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 23144142031 its reverse (13024144132), we get a palindrome (36168286163).
The spelling of 23144142031 in words is "twenty-three billion, one hundred forty-four million, one hundred forty-two thousand, thirty-one".
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