Base | Representation |
---|---|
bin | 10101100011100011… |
… | …101000101010000101 |
3 | 2012202000122001010221 |
4 | 111203203220222011 |
5 | 334400122404222 |
6 | 14344400144341 |
7 | 1446362203033 |
oct | 254343505205 |
9 | 65660561127 |
10 | 23145122437 |
11 | 98a7900068 |
12 | 459b3080b1 |
13 | 224b170c28 |
14 | 1197ca7553 |
15 | 906e290c7 |
hex | 5638e8a85 |
23145122437 has 2 divisors, whose sum is σ = 23145122438. Its totient is φ = 23145122436.
The previous prime is 23145122431. The next prime is 23145122461. The reversal of 23145122437 is 73422154132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18552891681 + 4592230756 = 136209^2 + 67766^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23145122437 is a prime.
It is a super-4 number, since 4×231451224374 (a number of 43 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23145122431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11572561218 + 11572561219.
It is an arithmetic number, because the mean of its divisors is an integer number (11572561219).
Almost surely, 223145122437 is an apocalyptic number.
It is an amenable number.
23145122437 is a deficient number, since it is larger than the sum of its proper divisors (1).
23145122437 is an equidigital number, since it uses as much as digits as its factorization.
23145122437 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40320, while the sum is 34.
Adding to 23145122437 its reverse (73422154132), we get a palindrome (96567276569).
The spelling of 23145122437 in words is "twenty-three billion, one hundred forty-five million, one hundred twenty-two thousand, four hundred thirty-seven".
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