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23151000131 = 73307285733
BaseRepresentation
bin10101100011111010…
…000011101001000011
32012202102200122211022
4111203322003221003
5334403124001011
614345130140055
71446463153130
oct254372035103
965672618738
1023151000131
119900155066
1245a128162b
13224c44b35c
141198997587
159076da8db
hex563e83a43

23151000131 has 4 divisors (see below), whose sum is σ = 26458285872. Its totient is φ = 19843714392.

The previous prime is 23151000127. The next prime is 23151000139. The reversal of 23151000131 is 13100015132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23151000131 - 22 = 23151000127 is a prime.

It is a super-2 number, since 2×231510001312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23151000139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1653642860 + ... + 1653642873.

It is an arithmetic number, because the mean of its divisors is an integer number (6614571468).

Almost surely, 223151000131 is an apocalyptic number.

23151000131 is a deficient number, since it is larger than the sum of its proper divisors (3307285741).

23151000131 is an equidigital number, since it uses as much as digits as its factorization.

23151000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3307285740.

The product of its (nonzero) digits is 90, while the sum is 17.

Adding to 23151000131 its reverse (13100015132), we get a palindrome (36251015263).

The spelling of 23151000131 in words is "twenty-three billion, one hundred fifty-one million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 7 3307285733 23151000131