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23151153050230 = 2511292050589287
BaseRepresentation
bin1010100001110010011000…
…10000001111001001110110
310000222020011122212022112111
411100321030100033021312
511013302030140101410
6121123254244041234
74606421104013512
oct520711420171166
9100866148768474
1023151153050230
117416392390637
12271aa2239321a
13cbc1b522961a
145a0743ad3142
152a233451db8a
hex150e4c40f276

23151153050230 has 16 divisors (see below), whose sum is σ = 41708986117920. Its totient is φ = 9252258858432.

The previous prime is 23151153050213. The next prime is 23151153050251. The reversal of 23151153050230 is 3205035115132.

It is a super-4 number, since 4×231511530502304 (a number of 55 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23151153050192 and 23151153050201.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1025283354 + ... + 1025305933.

It is an arithmetic number, because the mean of its divisors is an integer number (2606811632370).

Almost surely, 223151153050230 is an apocalyptic number.

23151153050230 is a deficient number, since it is larger than the sum of its proper divisors (18557833067690).

23151153050230 is a wasteful number, since it uses less digits than its factorization.

23151153050230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2050590423.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 23151153050230 its reverse (3205035115132), we get a palindrome (26356188165362).

The spelling of 23151153050230 in words is "twenty-three trillion, one hundred fifty-one billion, one hundred fifty-three million, fifty thousand, two hundred thirty".

Divisors: 1 2 5 10 1129 2258 5645 11290 2050589287 4101178574 10252946435 20505892870 2315115305023 4630230610046 11575576525115 23151153050230