Base | Representation |
---|---|
bin | 1010100001110010011000… |
… | …10000001111001001110110 |
3 | 10000222020011122212022112111 |
4 | 11100321030100033021312 |
5 | 11013302030140101410 |
6 | 121123254244041234 |
7 | 4606421104013512 |
oct | 520711420171166 |
9 | 100866148768474 |
10 | 23151153050230 |
11 | 7416392390637 |
12 | 271aa2239321a |
13 | cbc1b522961a |
14 | 5a0743ad3142 |
15 | 2a233451db8a |
hex | 150e4c40f276 |
23151153050230 has 16 divisors (see below), whose sum is σ = 41708986117920. Its totient is φ = 9252258858432.
The previous prime is 23151153050213. The next prime is 23151153050251. The reversal of 23151153050230 is 3205035115132.
It is a super-4 number, since 4×231511530502304 (a number of 55 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 23151153050192 and 23151153050201.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1025283354 + ... + 1025305933.
It is an arithmetic number, because the mean of its divisors is an integer number (2606811632370).
Almost surely, 223151153050230 is an apocalyptic number.
23151153050230 is a deficient number, since it is larger than the sum of its proper divisors (18557833067690).
23151153050230 is a wasteful number, since it uses less digits than its factorization.
23151153050230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2050590423.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 23151153050230 its reverse (3205035115132), we get a palindrome (26356188165362).
The spelling of 23151153050230 in words is "twenty-three trillion, one hundred fifty-one billion, one hundred fifty-three million, fifty thousand, two hundred thirty".
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