Base | Representation |
---|---|
bin | 110100101000111101101100… |
… | …111100110111011001000011 |
3 | 1010100201110200101121100100021 |
4 | 310220331230330313121003 |
5 | 220321104021203114024 |
6 | 2140215451035434311 |
7 | 66523203054131464 |
oct | 6450755474673103 |
9 | 1110643611540307 |
10 | 231513450051139 |
11 | 67849337013233 |
12 | 21b70a35bb5997 |
13 | 9c24817500469 |
14 | 412544ca78d6b |
15 | 1bb72e1e12de4 |
hex | d28f6cf37643 |
231513450051139 has 2 divisors, whose sum is σ = 231513450051140. Its totient is φ = 231513450051138.
The previous prime is 231513450051097. The next prime is 231513450051181. The reversal of 231513450051139 is 931150054315132.
It is a balanced prime because it is at equal distance from previous prime (231513450051097) and next prime (231513450051181).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-231513450051139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 231513450051095 and 231513450051104.
It is not a weakly prime, because it can be changed into another prime (231513450451139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115756725025569 + 115756725025570.
It is an arithmetic number, because the mean of its divisors is an integer number (115756725025570).
Almost surely, 2231513450051139 is an apocalyptic number.
231513450051139 is a deficient number, since it is larger than the sum of its proper divisors (1).
231513450051139 is an equidigital number, since it uses as much as digits as its factorization.
231513450051139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243000, while the sum is 43.
The spelling of 231513450051139 in words is "two hundred thirty-one trillion, five hundred thirteen billion, four hundred fifty million, fifty-one thousand, one hundred thirty-nine".
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