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231513450051139 is a prime number
BaseRepresentation
bin110100101000111101101100…
…111100110111011001000011
31010100201110200101121100100021
4310220331230330313121003
5220321104021203114024
62140215451035434311
766523203054131464
oct6450755474673103
91110643611540307
10231513450051139
1167849337013233
1221b70a35bb5997
139c24817500469
14412544ca78d6b
151bb72e1e12de4
hexd28f6cf37643

231513450051139 has 2 divisors, whose sum is σ = 231513450051140. Its totient is φ = 231513450051138.

The previous prime is 231513450051097. The next prime is 231513450051181. The reversal of 231513450051139 is 931150054315132.

It is a balanced prime because it is at equal distance from previous prime (231513450051097) and next prime (231513450051181).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-231513450051139 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 231513450051095 and 231513450051104.

It is not a weakly prime, because it can be changed into another prime (231513450451139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115756725025569 + 115756725025570.

It is an arithmetic number, because the mean of its divisors is an integer number (115756725025570).

Almost surely, 2231513450051139 is an apocalyptic number.

231513450051139 is a deficient number, since it is larger than the sum of its proper divisors (1).

231513450051139 is an equidigital number, since it uses as much as digits as its factorization.

231513450051139 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243000, while the sum is 43.

The spelling of 231513450051139 in words is "two hundred thirty-one trillion, five hundred thirteen billion, four hundred fifty million, fifty-one thousand, one hundred thirty-nine".