Base | Representation |
---|---|
bin | 110100101001001110011100… |
… | …000111100100000110100011 |
3 | 1010100210012001211121001012010 |
4 | 310221032130013210012203 |
5 | 220321402322320112201 |
6 | 2140232022213004003 |
7 | 66524410312625202 |
oct | 6451163407440643 |
9 | 1110705054531163 |
10 | 231531421254051 |
11 | 67855a19316a46 |
12 | 21b74410623603 |
13 | 9c2641c78a439 |
14 | 412627572b239 |
15 | 1bb79e49cdbd6 |
hex | d2939c1e41a3 |
231531421254051 has 32 divisors (see below), whose sum is σ = 325713895752960. Its totient is φ = 145889608190976.
The previous prime is 231531421254047. The next prime is 231531421254097. The reversal of 231531421254051 is 150452124135132.
It is not a de Polignac number, because 231531421254051 - 22 = 231531421254047 is a prime.
It is not an unprimeable number, because it can be changed into a prime (231531421254041) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 140179815 + ... + 141821871.
It is an arithmetic number, because the mean of its divisors is an integer number (10178559242280).
Almost surely, 2231531421254051 is an apocalyptic number.
231531421254051 is a deficient number, since it is larger than the sum of its proper divisors (94182474498909).
231531421254051 is a wasteful number, since it uses less digits than its factorization.
231531421254051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1647843.
The product of its (nonzero) digits is 144000, while the sum is 39.
Adding to 231531421254051 its reverse (150452124135132), we get a palindrome (381983545389183).
The spelling of 231531421254051 in words is "two hundred thirty-one trillion, five hundred thirty-one billion, four hundred twenty-one million, two hundred fifty-four thousand, fifty-one".
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