Base | Representation |
---|---|
bin | 10101100100000111… |
… | …000100101110011001 |
3 | 2012202200010000122011 |
4 | 111210013010232121 |
5 | 334410012144231 |
6 | 14345331225521 |
7 | 1446534154426 |
oct | 254407045631 |
9 | 65680100564 |
10 | 23154412441 |
11 | 9902075856 |
12 | 45a24482a1 |
13 | 2250074584 |
14 | 1199204d4d |
15 | 907b619b1 |
hex | 5641c4b99 |
23154412441 has 2 divisors, whose sum is σ = 23154412442. Its totient is φ = 23154412440.
The previous prime is 23154412427. The next prime is 23154412469. The reversal of 23154412441 is 14421445132.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14671265625 + 8483146816 = 121125^2 + 92104^2 .
It is a cyclic number.
It is not a de Polignac number, because 23154412441 - 27 = 23154412313 is a prime.
It is a super-2 number, since 2×231544124412 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (23154412241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11577206220 + 11577206221.
It is an arithmetic number, because the mean of its divisors is an integer number (11577206221).
Almost surely, 223154412441 is an apocalyptic number.
It is an amenable number.
23154412441 is a deficient number, since it is larger than the sum of its proper divisors (1).
23154412441 is an equidigital number, since it uses as much as digits as its factorization.
23154412441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15360, while the sum is 31.
Adding to 23154412441 its reverse (14421445132), we get a palindrome (37575857573).
The spelling of 23154412441 in words is "twenty-three billion, one hundred fifty-four million, four hundred twelve thousand, four hundred forty-one".
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