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23154412441 is a prime number
BaseRepresentation
bin10101100100000111…
…000100101110011001
32012202200010000122011
4111210013010232121
5334410012144231
614345331225521
71446534154426
oct254407045631
965680100564
1023154412441
119902075856
1245a24482a1
132250074584
141199204d4d
15907b619b1
hex5641c4b99

23154412441 has 2 divisors, whose sum is σ = 23154412442. Its totient is φ = 23154412440.

The previous prime is 23154412427. The next prime is 23154412469. The reversal of 23154412441 is 14421445132.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14671265625 + 8483146816 = 121125^2 + 92104^2 .

It is a cyclic number.

It is not a de Polignac number, because 23154412441 - 27 = 23154412313 is a prime.

It is a super-2 number, since 2×231544124412 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (23154412241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11577206220 + 11577206221.

It is an arithmetic number, because the mean of its divisors is an integer number (11577206221).

Almost surely, 223154412441 is an apocalyptic number.

It is an amenable number.

23154412441 is a deficient number, since it is larger than the sum of its proper divisors (1).

23154412441 is an equidigital number, since it uses as much as digits as its factorization.

23154412441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15360, while the sum is 31.

Adding to 23154412441 its reverse (14421445132), we get a palindrome (37575857573).

The spelling of 23154412441 in words is "twenty-three billion, one hundred fifty-four million, four hundred twelve thousand, four hundred forty-one".