Base | Representation |
---|---|
bin | 1101011110100101110… |
… | …1101001111011000011 |
3 | 211010200010102110002101 |
4 | 3113221131221323003 |
5 | 12243203313210112 |
6 | 254212254531231 |
7 | 22505012434603 |
oct | 3275135517303 |
9 | 733603373071 |
10 | 231550131907 |
11 | 8a222016286 |
12 | 38a61806b17 |
13 | 18ab18a9993 |
14 | b2c835cc03 |
15 | 60531eb757 |
hex | 35e9769ec3 |
231550131907 has 2 divisors, whose sum is σ = 231550131908. Its totient is φ = 231550131906.
The previous prime is 231550131887. The next prime is 231550131947. The reversal of 231550131907 is 709131055132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 231550131907 - 211 = 231550129859 is a prime.
It is a super-3 number, since 3×2315501319073 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (231550131947) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115775065953 + 115775065954.
It is an arithmetic number, because the mean of its divisors is an integer number (115775065954).
Almost surely, 2231550131907 is an apocalyptic number.
231550131907 is a deficient number, since it is larger than the sum of its proper divisors (1).
231550131907 is an equidigital number, since it uses as much as digits as its factorization.
231550131907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28350, while the sum is 37.
The spelling of 231550131907 in words is "two hundred thirty-one billion, five hundred fifty million, one hundred thirty-one thousand, nine hundred seven".
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