Base | Representation |
---|---|
bin | 110100110000000100001001… |
… | …110100010001100101100111 |
3 | 1010102110010012101012221011020 |
4 | 310300010021310101211213 |
5 | 220402102343230022003 |
6 | 2141231551113542223 |
7 | 66603356202625326 |
oct | 6460041164214547 |
9 | 1112403171187136 |
10 | 232001413126503 |
11 | 67a1727949a029 |
12 | 2202b517a14973 |
13 | 9c5b840958907 |
14 | 4140cdd3cc0bd |
15 | 1bc4d50e2ed53 |
hex | d30109d11967 |
232001413126503 has 8 divisors (see below), whose sum is σ = 313692051551616. Its totient is φ = 152489191726200.
The previous prime is 232001413126423. The next prime is 232001413126507. The reversal of 232001413126503 is 305621314100232.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 232001413126503 - 29 = 232001413125991 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (232001413126507) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 544604255953 + ... + 544604256378.
It is an arithmetic number, because the mean of its divisors is an integer number (39211506443952).
Almost surely, 2232001413126503 is an apocalyptic number.
232001413126503 is a deficient number, since it is larger than the sum of its proper divisors (81690638425113).
232001413126503 is a wasteful number, since it uses less digits than its factorization.
232001413126503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1089208512405.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 232001413126503 its reverse (305621314100232), we get a palindrome (537622727226735).
The spelling of 232001413126503 in words is "two hundred thirty-two trillion, one billion, four hundred thirteen million, one hundred twenty-six thousand, five hundred three".
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