Base | Representation |
---|---|
bin | 100001110000101100100… |
… | …101101101000010010111 |
3 | 22012210101220112200220221 |
4 | 201300230211231002113 |
5 | 301002410241434033 |
6 | 4533450211335211 |
7 | 326421342125611 |
oct | 41605445550227 |
9 | 8183356480827 |
10 | 2320030421143 |
11 | 814a12764a46 |
12 | 3157795b1507 |
13 | 13aa1615c486 |
14 | 8040bd55db1 |
15 | 40538e1612d |
hex | 21c2c96d097 |
2320030421143 has 4 divisors (see below), whose sum is σ = 2327587523800. Its totient is φ = 2312473318488.
The previous prime is 2320030421141. The next prime is 2320030421161. The reversal of 2320030421143 is 3411240300232.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2320030421143 - 21 = 2320030421141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2320030421141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3778550868 + ... + 3778551481.
It is an arithmetic number, because the mean of its divisors is an integer number (581896880950).
Almost surely, 22320030421143 is an apocalyptic number.
2320030421143 is a deficient number, since it is larger than the sum of its proper divisors (7557102657).
2320030421143 is an equidigital number, since it uses as much as digits as its factorization.
2320030421143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7557102656.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 2320030421143 its reverse (3411240300232), we get a palindrome (5731270721375).
The spelling of 2320030421143 in words is "two trillion, three hundred twenty billion, thirty million, four hundred twenty-one thousand, one hundred forty-three".
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