Base | Representation |
---|---|
bin | 1010100011001111011110… |
… | …10000000010000110000111 |
3 | 10001011000011210200110000211 |
4 | 11101213233100002012013 |
5 | 11020111404333320312 |
6 | 121202241505220251 |
7 | 4613140454561566 |
oct | 521475720020607 |
9 | 101130153613024 |
10 | 23201132323207 |
11 | 74355aa387113 |
12 | 2728650331687 |
13 | cc3b1b8c0027 |
14 | 5a2d25789bdd |
15 | 2a37ac16c3a7 |
hex | 1519ef402187 |
23201132323207 has 2 divisors, whose sum is σ = 23201132323208. Its totient is φ = 23201132323206.
The previous prime is 23201132323177. The next prime is 23201132323223. The reversal of 23201132323207 is 70232323110232.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23201132323207 - 231 = 23198984839559 is a prime.
It is a super-2 number, since 2×232011323232072 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23201132323247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11600566161603 + 11600566161604.
It is an arithmetic number, because the mean of its divisors is an integer number (11600566161604).
Almost surely, 223201132323207 is an apocalyptic number.
23201132323207 is a deficient number, since it is larger than the sum of its proper divisors (1).
23201132323207 is an equidigital number, since it uses as much as digits as its factorization.
23201132323207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 31.
Adding to 23201132323207 its reverse (70232323110232), we get a palindrome (93433455433439).
The spelling of 23201132323207 in words is "twenty-three trillion, two hundred one billion, one hundred thirty-two million, three hundred twenty-three thousand, two hundred seven".
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