Base | Representation |
---|---|
bin | 1101100000010100000… |
… | …0011001001111001101 |
3 | 211011212022221010111111 |
4 | 3120011000121033031 |
5 | 12300130112122222 |
6 | 254330203052021 |
7 | 22522323234331 |
oct | 3300500311715 |
9 | 734768833444 |
10 | 232012223437 |
11 | 8a439940505 |
12 | 38b70511011 |
13 | 18b5654b217 |
14 | b32d8877c1 |
15 | 607da77777 |
hex | 36050193cd |
232012223437 has 2 divisors, whose sum is σ = 232012223438. Its totient is φ = 232012223436.
The previous prime is 232012223389. The next prime is 232012223447. The reversal of 232012223437 is 734322210232.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 211373740516 + 20638482921 = 459754^2 + 143661^2 .
It is a cyclic number.
It is not a de Polignac number, because 232012223437 - 27 = 232012223309 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 232012223399 and 232012223408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (232012223447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116006111718 + 116006111719.
It is an arithmetic number, because the mean of its divisors is an integer number (116006111719).
Almost surely, 2232012223437 is an apocalyptic number.
It is an amenable number.
232012223437 is a deficient number, since it is larger than the sum of its proper divisors (1).
232012223437 is an equidigital number, since it uses as much as digits as its factorization.
232012223437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 31.
Adding to 232012223437 its reverse (734322210232), we get a palindrome (966334433669).
The spelling of 232012223437 in words is "two hundred thirty-two billion, twelve million, two hundred twenty-three thousand, four hundred thirty-seven".
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