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23201266740557 is a prime number
BaseRepresentation
bin1010100011001111101110…
…10000110010110101001101
310001011000112011121112222012
411101213313100302311031
511020112143241144212
6121202303110231005
74613144006241113
oct521476720626515
9101130464545865
1023201266740557
117435669245934
122728689355465
13cc3b406c4319
145a2d39579ab3
152a37b8d6e922
hex1519f7432d4d

23201266740557 has 2 divisors, whose sum is σ = 23201266740558. Its totient is φ = 23201266740556.

The previous prime is 23201266740433. The next prime is 23201266740599. The reversal of 23201266740557 is 75504766210232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22821458306761 + 379808433796 = 4777181^2 + 616286^2 .

It is a cyclic number.

It is not a de Polignac number, because 23201266740557 - 218 = 23201266478413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23201266740257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11600633370278 + 11600633370279.

It is an arithmetic number, because the mean of its divisors is an integer number (11600633370279).

Almost surely, 223201266740557 is an apocalyptic number.

It is an amenable number.

23201266740557 is a deficient number, since it is larger than the sum of its proper divisors (1).

23201266740557 is an equidigital number, since it uses as much as digits as its factorization.

23201266740557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4233600, while the sum is 50.

The spelling of 23201266740557 in words is "twenty-three trillion, two hundred one billion, two hundred sixty-six million, seven hundred forty thousand, five hundred fifty-seven".