Base | Representation |
---|---|
bin | 1101100000010100101… |
… | …1001001001010111101 |
3 | 211011212112020021202120 |
4 | 3120011023021022331 |
5 | 12300131322304323 |
6 | 254330343313153 |
7 | 22522356211404 |
oct | 3300513111275 |
9 | 734775207676 |
10 | 232015041213 |
11 | 8a44049554a |
12 | 38b7144b7b9 |
13 | 18b56cc6947 |
14 | b32ddbc63b |
15 | 607de325e3 |
hex | 36052c92bd |
232015041213 has 4 divisors (see below), whose sum is σ = 309353388288. Its totient is φ = 154676694140.
The previous prime is 232015041173. The next prime is 232015041329. The reversal of 232015041213 is 312140510232.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 232015041213 - 213 = 232015033021 is a prime.
It is a super-2 number, since 2×2320150412132 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (232015041613) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38669173533 + ... + 38669173538.
It is an arithmetic number, because the mean of its divisors is an integer number (77338347072).
Almost surely, 2232015041213 is an apocalyptic number.
It is an amenable number.
232015041213 is a deficient number, since it is larger than the sum of its proper divisors (77338347075).
232015041213 is an equidigital number, since it uses as much as digits as its factorization.
232015041213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77338347074.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 232015041213 its reverse (312140510232), we get a palindrome (544155551445).
The spelling of 232015041213 in words is "two hundred thirty-two billion, fifteen million, forty-one thousand, two hundred thirteen".
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