Base | Representation |
---|---|
bin | 110100110000100000110100… |
… | …111011110110011111010011 |
3 | 1010102120001200001121101211012 |
4 | 310300200310323312133103 |
5 | 220403103422013212034 |
6 | 2141254042143241135 |
7 | 66605526153050654 |
oct | 6460406473663723 |
9 | 1112501601541735 |
10 | 232032201304019 |
11 | 67a29338629536 |
12 | 2203548a8a91ab |
13 | 9c617093c462c |
14 | 41425c03a552b |
15 | 1bc5a53d47cce |
hex | d30834ef67d3 |
232032201304019 has 2 divisors, whose sum is σ = 232032201304020. Its totient is φ = 232032201304018.
The previous prime is 232032201303923. The next prime is 232032201304021. The reversal of 232032201304019 is 910403102230232.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 232032201304019 - 236 = 231963481827283 is a prime.
It is a super-2 number, since 2×2320322013040192 (a number of 30 digits) contains 22 as substring.
Together with 232032201304021, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (232032201304049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116016100652009 + 116016100652010.
It is an arithmetic number, because the mean of its divisors is an integer number (116016100652010).
Almost surely, 2232032201304019 is an apocalyptic number.
232032201304019 is a deficient number, since it is larger than the sum of its proper divisors (1).
232032201304019 is an equidigital number, since it uses as much as digits as its factorization.
232032201304019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 32.
The spelling of 232032201304019 in words is "two hundred thirty-two trillion, thirty-two billion, two hundred one million, three hundred four thousand, nineteen".
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