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23213320141397 is a prime number
BaseRepresentation
bin1010100011100110001011…
…01100110111101001010101
310001012011122012012202111112
411101303011230313221111
511020311334424011042
6121212015124344405
74614051466405331
oct521630554675125
9101164565182445
1023213320141397
11743a794060331
12272aa91b45105
13cc5011935179
145a37602d87c1
152a3c7213c982
hex151cc5b37a55

23213320141397 has 2 divisors, whose sum is σ = 23213320141398. Its totient is φ = 23213320141396.

The previous prime is 23213320141381. The next prime is 23213320141469. The reversal of 23213320141397 is 79314102331232.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11692631463601 + 11520688677796 = 3419449^2 + 3394214^2 .

It is a cyclic number.

It is not a de Polignac number, because 23213320141397 - 24 = 23213320141381 is a prime.

It is a super-3 number, since 3×232133201413973 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23213320141327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11606660070698 + 11606660070699.

It is an arithmetic number, because the mean of its divisors is an integer number (11606660070699).

Almost surely, 223213320141397 is an apocalyptic number.

It is an amenable number.

23213320141397 is a deficient number, since it is larger than the sum of its proper divisors (1).

23213320141397 is an equidigital number, since it uses as much as digits as its factorization.

23213320141397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 163296, while the sum is 41.

The spelling of 23213320141397 in words is "twenty-three trillion, two hundred thirteen billion, three hundred twenty million, one hundred forty-one thousand, three hundred ninety-seven".