Base | Representation |
---|---|
bin | 1101100000110010011… |
… | …1110111011100100111 |
3 | 211012012020101102111102 |
4 | 3120030213313130213 |
5 | 12300410320330203 |
6 | 254351010030315 |
7 | 22525434352604 |
oct | 3301447673447 |
9 | 735166342442 |
10 | 232140011303 |
11 | 8a4a4a91412 |
12 | 38ba727839b |
13 | 18b76b70b45 |
14 | b34282d6ab |
15 | 6089dba888 |
hex | 360c9f7727 |
232140011303 has 2 divisors, whose sum is σ = 232140011304. Its totient is φ = 232140011302.
The previous prime is 232140011249. The next prime is 232140011309. The reversal of 232140011303 is 303110041232.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 232140011303 - 218 = 232139749159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (232140011309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116070005651 + 116070005652.
It is an arithmetic number, because the mean of its divisors is an integer number (116070005652).
Almost surely, 2232140011303 is an apocalyptic number.
232140011303 is a deficient number, since it is larger than the sum of its proper divisors (1).
232140011303 is an equidigital number, since it uses as much as digits as its factorization.
232140011303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 232140011303 its reverse (303110041232), we get a palindrome (535250052535).
The spelling of 232140011303 in words is "two hundred thirty-two billion, one hundred forty million, eleven thousand, three hundred three".
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