Base | Representation |
---|---|
bin | 1101100000110010111… |
… | …1101001011100111011 |
3 | 211012012101020001121121 |
4 | 3120030233221130323 |
5 | 12300411331114011 |
6 | 254351121450111 |
7 | 22525460606614 |
oct | 3301457513473 |
9 | 735171201547 |
10 | 232142051131 |
11 | 8a4a6154a21 |
12 | 38ba7aa0937 |
13 | 18b77406443 |
14 | b342c00c0b |
15 | 608a16ee71 |
hex | 360cbe973b |
232142051131 has 4 divisors (see below), whose sum is σ = 232898214472. Its totient is φ = 231385887792.
The previous prime is 232142051083. The next prime is 232142051143. The reversal of 232142051131 is 131150241232.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 232142051131 - 27 = 232142051003 is a prime.
It is a super-2 number, since 2×2321420511312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 232142051096 and 232142051105.
It is not an unprimeable number, because it can be changed into a prime (232142051171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 378081210 + ... + 378081823.
It is an arithmetic number, because the mean of its divisors is an integer number (58224553618).
Almost surely, 2232142051131 is an apocalyptic number.
232142051131 is a deficient number, since it is larger than the sum of its proper divisors (756163341).
232142051131 is an equidigital number, since it uses as much as digits as its factorization.
232142051131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 756163340.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 232142051131 its reverse (131150241232), we get a palindrome (363292292363).
The spelling of 232142051131 in words is "two hundred thirty-two billion, one hundred forty-two million, fifty-one thousand, one hundred thirty-one".
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