Base | Representation |
---|---|
bin | 111101000100100101… |
… | …0011101110111010000 |
3 | 110112112002022112221221 |
4 | 1322021022131313100 |
5 | 4122043430204412 |
6 | 140125524454424 |
7 | 12322011441223 |
oct | 1721112356720 |
9 | 415462275857 |
10 | 131150241232 |
11 | 5069098a41a |
12 | 21501b4a414 |
13 | c4a129664a |
14 | 64c21655ba |
15 | 3628d20b07 |
hex | 1e8929ddd0 |
131150241232 has 10 divisors (see below), whose sum is σ = 254103592418. Its totient is φ = 65575120608.
The previous prime is 131150241227. The next prime is 131150241251. The reversal of 131150241232 is 232142051131.
It can be written as a sum of positive squares in only one way, i.e., 91770220096 + 39380021136 = 302936^2 + 198444^2 .
It is a junction number, because it is equal to n+sod(n) for n = 131150241197 and 131150241206.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4098445023 + ... + 4098445054.
Almost surely, 2131150241232 is an apocalyptic number.
It is an amenable number.
131150241232 is a deficient number, since it is larger than the sum of its proper divisors (122953351186).
131150241232 is an equidigital number, since it uses as much as digits as its factorization.
131150241232 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8196890085 (or 8196890079 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 131150241232 its reverse (232142051131), we get a palindrome (363292292363).
The spelling of 131150241232 in words is "one hundred thirty-one billion, one hundred fifty million, two hundred forty-one thousand, two hundred thirty-two".
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