Base | Representation |
---|---|
bin | 10101101000001001… |
… | …010010110110001001 |
3 | 2012221101111002012221 |
4 | 111220021102312021 |
5 | 340024324302213 |
6 | 14400150134041 |
7 | 1451315423314 |
oct | 255011226611 |
9 | 65841432187 |
10 | 23222103433 |
11 | 99372aa021 |
12 | 4601051321 |
13 | 22610b5109 |
14 | 11a41c597b |
15 | 90da8338d |
hex | 568252d89 |
23222103433 has 8 divisors (see below), whose sum is σ = 24234065856. Its totient is φ = 22210333200.
The previous prime is 23222103427. The next prime is 23222103461. The reversal of 23222103433 is 33430122232.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 23222103433 - 29 = 23222102921 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23222103398 and 23222103407.
It is not an unprimeable number, because it can be changed into a prime (23222101433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 234223 + ... + 318283.
It is an arithmetic number, because the mean of its divisors is an integer number (3029258232).
Almost surely, 223222103433 is an apocalyptic number.
23222103433 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
23222103433 is a deficient number, since it is larger than the sum of its proper divisors (1011962423).
23222103433 is a wasteful number, since it uses less digits than its factorization.
23222103433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96095.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 23222103433 its reverse (33430122232), we get a palindrome (56652225665).
The spelling of 23222103433 in words is "twenty-three billion, two hundred twenty-two million, one hundred three thousand, four hundred thirty-three".
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