Base | Representation |
---|---|
bin | 1010100011111000100111… |
… | …10111100111000010100011 |
3 | 10001020010012020101121211021 |
4 | 11101330103313213002203 |
5 | 11020442124201430103 |
6 | 121220333425230311 |
7 | 4614552035604121 |
oct | 521742367470243 |
9 | 101203166347737 |
10 | 23223221514403 |
11 | 7443a05131429 |
12 | 2730995a92397 |
13 | cc5c2c06ca71 |
14 | 5a401d306911 |
15 | 2a4151517bbd |
hex | 151f13de70a3 |
23223221514403 has 2 divisors, whose sum is σ = 23223221514404. Its totient is φ = 23223221514402.
The previous prime is 23223221514401. The next prime is 23223221514419. The reversal of 23223221514403 is 30441512232232.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23223221514403 - 21 = 23223221514401 is a prime.
Together with 23223221514401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (23223221514401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11611610757201 + 11611610757202.
It is an arithmetic number, because the mean of its divisors is an integer number (11611610757202).
Almost surely, 223223221514403 is an apocalyptic number.
23223221514403 is a deficient number, since it is larger than the sum of its proper divisors (1).
23223221514403 is an equidigital number, since it uses as much as digits as its factorization.
23223221514403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 23223221514403 its reverse (30441512232232), we get a palindrome (53664733746635).
The spelling of 23223221514403 in words is "twenty-three trillion, two hundred twenty-three billion, two hundred twenty-one million, five hundred fourteen thousand, four hundred three".
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