23224341340049 has 2 divisors, whose sum is σ = 23224341340050. Its totient is φ = 23224341340048.

The previous prime is 23224341340043. The next prime is 23224341340051. The reversal of 23224341340049 is 94004314342232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13896008230225 + 9328333109824 = 3727735^2 + 3054232^2 .

It is a cyclic number.

It is not a de Polignac number, because 23224341340049 - 2³² = 23220046372753 is a prime.

Together with 23224341340051, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 23224341339988 and 23224341340015.

It is not a weakly prime, because it can be changed into another prime (23224341340043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11612170670024 + 11612170670025.

It is an arithmetic number, because the mean of its divisors is an integer number (11612170670025).

Almost surely, 2^{23224341340049} is an apocalyptic number.

It is an amenable number.

23224341340049 is a deficient number, since it is larger than the sum of its proper divisors (1).

23224341340049 is an equidigital number, since it uses as much as digits as its factorization.

23224341340049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 497664, while the sum is 41.

The spelling of 23224341340049 in words is "twenty-three trillion, two hundred twenty-four billion, three hundred forty-one million, three hundred forty thousand, forty-nine".