Base | Representation |
---|---|
bin | 1010100011111100111001… |
… | …01101011111010111001111 |
3 | 10001020100010020101122122001 |
4 | 11101332130231133113033 |
5 | 11021011324414340421 |
6 | 121221353320533131 |
7 | 4614662654031412 |
oct | 521763455372717 |
9 | 101210106348561 |
10 | 23225517340111 |
11 | 7444983061249 |
12 | 27313169211a7 |
13 | cc62068b2c08 |
14 | 5a419a1a9b79 |
15 | 2a4237d62691 |
hex | 151f9cb5f5cf |
23225517340111 has 2 divisors, whose sum is σ = 23225517340112. Its totient is φ = 23225517340110.
The previous prime is 23225517340097. The next prime is 23225517340141. The reversal of 23225517340111 is 11104371552232.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23225517340111 - 221 = 23225515242959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23225517340141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11612758670055 + 11612758670056.
It is an arithmetic number, because the mean of its divisors is an integer number (11612758670056).
Almost surely, 223225517340111 is an apocalyptic number.
23225517340111 is a deficient number, since it is larger than the sum of its proper divisors (1).
23225517340111 is an equidigital number, since it uses as much as digits as its factorization.
23225517340111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50400, while the sum is 37.
Adding to 23225517340111 its reverse (11104371552232), we get a palindrome (34329888892343).
The spelling of 23225517340111 in words is "twenty-three trillion, two hundred twenty-five billion, five hundred seventeen million, three hundred forty thousand, one hundred eleven".
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