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23230005433 = 67893895691
BaseRepresentation
bin10101101000100111…
…011100000010111001
32012221221100112201121
4111220213130002321
5340033340133213
614401031345241
71451442534235
oct255047340271
965857315647
1023230005433
1199408069a8
124603822221
132262920a5b
1411a52815c5
1590e5e488d
hex5689dc0b9

23230005433 has 8 divisors (see below), whose sum is σ = 23841635040. Its totient is φ = 22626167520.

The previous prime is 23230005431. The next prime is 23230005437. The reversal of 23230005433 is 33450003232.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 23230005433 - 21 = 23230005431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23230005398 and 23230005407.

It is not an unprimeable number, because it can be changed into a prime (23230005431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1941883 + ... + 1953808.

It is an arithmetic number, because the mean of its divisors is an integer number (2980204380).

Almost surely, 223230005433 is an apocalyptic number.

It is an amenable number.

23230005433 is a deficient number, since it is larger than the sum of its proper divisors (611629607).

23230005433 is an equidigital number, since it uses as much as digits as its factorization.

23230005433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3895847.

The product of its (nonzero) digits is 6480, while the sum is 25.

Adding to 23230005433 its reverse (33450003232), we get a palindrome (56680008665).

The spelling of 23230005433 in words is "twenty-three billion, two hundred thirty million, five thousand, four hundred thirty-three".

Divisors: 1 67 89 5963 3895691 261011297 346716499 23230005433