Base | Representation |
---|---|
bin | 1010100100000101010001… |
… | …10111011100110110011011 |
3 | 10001020202201202212201010111 |
4 | 11102002220313130312123 |
5 | 11021100033124321042 |
6 | 121223415552025151 |
7 | 4615212313061545 |
oct | 522025067346633 |
9 | 101222652781114 |
10 | 23230016245147 |
11 | 7446881624188 |
12 | 27321715321b7 |
13 | cc67729951ba |
14 | 5a44a58ac695 |
15 | 2a43eccd6517 |
hex | 1520a8ddcd9b |
23230016245147 has 2 divisors, whose sum is σ = 23230016245148. Its totient is φ = 23230016245146.
The previous prime is 23230016245063. The next prime is 23230016245217. The reversal of 23230016245147 is 74154261003232.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23230016245147 - 215 = 23230016212379 is a prime.
It is not a weakly prime, because it can be changed into another prime (23230016245747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11615008122573 + 11615008122574.
It is an arithmetic number, because the mean of its divisors is an integer number (11615008122574).
Almost surely, 223230016245147 is an apocalyptic number.
23230016245147 is a deficient number, since it is larger than the sum of its proper divisors (1).
23230016245147 is an equidigital number, since it uses as much as digits as its factorization.
23230016245147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 241920, while the sum is 40.
Adding to 23230016245147 its reverse (74154261003232), we get a palindrome (97384277248379).
The spelling of 23230016245147 in words is "twenty-three trillion, two hundred thirty billion, sixteen million, two hundred forty-five thousand, one hundred forty-seven".
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