Base | Representation |
---|---|
bin | 1101100001011011110… |
… | …0100100010010111111 |
3 | 211012122022021211111201 |
4 | 3120112330210102333 |
5 | 12301234140210142 |
6 | 254420114200331 |
7 | 22532636463322 |
oct | 3302674442277 |
9 | 735568254451 |
10 | 232313210047 |
11 | 8a583829176 |
12 | 390352830a7 |
13 | 18ba3a030c9 |
14 | b35b8367b9 |
15 | 609a1cdab7 |
hex | 3616f244bf |
232313210047 has 2 divisors, whose sum is σ = 232313210048. Its totient is φ = 232313210046.
The previous prime is 232313210029. The next prime is 232313210057. The reversal of 232313210047 is 740012313232.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 232313210047 - 223 = 232304821439 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 232313209997 and 232313210024.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (232313210057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116156605023 + 116156605024.
It is an arithmetic number, because the mean of its divisors is an integer number (116156605024).
Almost surely, 2232313210047 is an apocalyptic number.
232313210047 is a deficient number, since it is larger than the sum of its proper divisors (1).
232313210047 is an equidigital number, since it uses as much as digits as its factorization.
232313210047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 232313210047 its reverse (740012313232), we get a palindrome (972325523279).
It can be divided in two parts, 2323 and 13210047, that added together give a triangular number (13212370 = T5140).
The spelling of 232313210047 in words is "two hundred thirty-two billion, three hundred thirteen million, two hundred ten thousand, forty-seven".
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