Base | Representation |
---|---|
bin | 1010100100001101010100… |
… | …00000101100000100101111 |
3 | 10001021011212102202001112111 |
4 | 11102012222000230010233 |
5 | 11021132402041130221 |
6 | 121225412023344451 |
7 | 4615424236635505 |
oct | 522065200540457 |
9 | 101234772661474 |
10 | 23234330411311 |
11 | 7448695888068 |
12 | 2732b762b2127 |
13 | cc6cac704646 |
14 | 5a4794842675 |
15 | 2a45a1917be1 |
hex | 1521aa02c12f |
23234330411311 has 4 divisors (see below), whose sum is σ = 23234633962624. Its totient is φ = 23234026860000.
The previous prime is 23234330411309. The next prime is 23234330411317. The reversal of 23234330411311 is 11311403343232.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23234330411311 - 21 = 23234330411309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23234330411317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151660815 + ... + 151813936.
It is an arithmetic number, because the mean of its divisors is an integer number (5808658490656).
Almost surely, 223234330411311 is an apocalyptic number.
23234330411311 is a deficient number, since it is larger than the sum of its proper divisors (303551313).
23234330411311 is an equidigital number, since it uses as much as digits as its factorization.
23234330411311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 303551312.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 23234330411311 its reverse (11311403343232), we get a palindrome (34545733754543).
The spelling of 23234330411311 in words is "twenty-three trillion, two hundred thirty-four billion, three hundred thirty million, four hundred eleven thousand, three hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •