Base | Representation |
---|---|
bin | 1010100100011111110000… |
… | …01001101111000110001011 |
3 | 10001022010102110002100221212 |
4 | 11102033320021233012023 |
5 | 11021313141210343202 |
6 | 121234130310523335 |
7 | 4616224502305166 |
oct | 522177011570613 |
9 | 101263373070855 |
10 | 23244231340427 |
11 | 7451906685709 |
12 | 2734a7a06654b |
13 | cc7bc9a15196 |
14 | 5a5053776add |
15 | 2a4980c56652 |
hex | 1523f826f18b |
23244231340427 has 2 divisors, whose sum is σ = 23244231340428. Its totient is φ = 23244231340426.
The previous prime is 23244231340387. The next prime is 23244231340483. The reversal of 23244231340427 is 72404313244232.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23244231340427 - 240 = 22144719712651 is a prime.
It is not a weakly prime, because it can be changed into another prime (23244231340027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11622115670213 + 11622115670214.
It is an arithmetic number, because the mean of its divisors is an integer number (11622115670214).
Almost surely, 223244231340427 is an apocalyptic number.
23244231340427 is a deficient number, since it is larger than the sum of its proper divisors (1).
23244231340427 is an equidigital number, since it uses as much as digits as its factorization.
23244231340427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 774144, while the sum is 41.
Adding to 23244231340427 its reverse (72404313244232), we get a palindrome (95648544584659).
The spelling of 23244231340427 in words is "twenty-three trillion, two hundred forty-four billion, two hundred thirty-one million, three hundred forty thousand, four hundred twenty-seven".
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