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23244312433 = 47494559839
BaseRepresentation
bin10101101001011110…
…000000111101110001
32012222221021102020111
4111221132000331301
5340101020444213
614402302141321
71452005252506
oct255136007561
965887242214
1023244312433
119948898a71
124608581841
13226588cb34
1411a71274ad
159109bda3d
hex569780f71

23244312433 has 4 divisors (see below), whose sum is σ = 23738872320. Its totient is φ = 22749752548.

The previous prime is 23244312379. The next prime is 23244312467. The reversal of 23244312433 is 33421344232.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23244312433 - 29 = 23244311921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23244312395 and 23244312404.

It is not an unprimeable number, because it can be changed into a prime (23244112433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 247279873 + ... + 247279966.

It is an arithmetic number, because the mean of its divisors is an integer number (5934718080).

Almost surely, 223244312433 is an apocalyptic number.

It is an amenable number.

23244312433 is a deficient number, since it is larger than the sum of its proper divisors (494559887).

23244312433 is an equidigital number, since it uses as much as digits as its factorization.

23244312433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 494559886.

The product of its digits is 41472, while the sum is 31.

Adding to 23244312433 its reverse (33421344232), we get a palindrome (56665656665).

The spelling of 23244312433 in words is "twenty-three billion, two hundred forty-four million, three hundred twelve thousand, four hundred thirty-three".

Divisors: 1 47 494559839 23244312433