Base | Representation |
---|---|
bin | 1010100110001111010110… |
… | …00000110100111000001111 |
3 | 10001111212001121122010002022 |
4 | 11103013223000310320033 |
5 | 11023303334423140101 |
6 | 121321435130520355 |
7 | 4623445216262231 |
oct | 523075300647017 |
9 | 101455047563068 |
10 | 23304140443151 |
11 | 7475259819257 |
12 | 27445b95960bb |
13 | 1000756697ba9 |
14 | 5a7cd8128251 |
15 | 2a62da501a1b |
hex | 1531eb034e0f |
23304140443151 has 4 divisors (see below), whose sum is σ = 23305037437704. Its totient is φ = 23303243448600.
The previous prime is 23304140443037. The next prime is 23304140443153. The reversal of 23304140443151 is 15134404140332.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23304140443151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23304140443153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 448458305 + ... + 448510266.
It is an arithmetic number, because the mean of its divisors is an integer number (5826259359426).
Almost surely, 223304140443151 is an apocalyptic number.
23304140443151 is a deficient number, since it is larger than the sum of its proper divisors (896994553).
23304140443151 is an equidigital number, since it uses as much as digits as its factorization.
23304140443151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 896994552.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 23304140443151 its reverse (15134404140332), we get a palindrome (38438544583483).
The spelling of 23304140443151 in words is "twenty-three trillion, three hundred four billion, one hundred forty million, four hundred forty-three thousand, one hundred fifty-one".
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