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23304140443151 = 25981896968571
BaseRepresentation
bin1010100110001111010110…
…00000110100111000001111
310001111212001121122010002022
411103013223000310320033
511023303334423140101
6121321435130520355
74623445216262231
oct523075300647017
9101455047563068
1023304140443151
117475259819257
1227445b95960bb
131000756697ba9
145a7cd8128251
152a62da501a1b
hex1531eb034e0f

23304140443151 has 4 divisors (see below), whose sum is σ = 23305037437704. Its totient is φ = 23303243448600.

The previous prime is 23304140443037. The next prime is 23304140443153. The reversal of 23304140443151 is 15134404140332.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23304140443151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23304140443153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 448458305 + ... + 448510266.

It is an arithmetic number, because the mean of its divisors is an integer number (5826259359426).

Almost surely, 223304140443151 is an apocalyptic number.

23304140443151 is a deficient number, since it is larger than the sum of its proper divisors (896994553).

23304140443151 is an equidigital number, since it uses as much as digits as its factorization.

23304140443151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 896994552.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 23304140443151 its reverse (15134404140332), we get a palindrome (38438544583483).

The spelling of 23304140443151 in words is "twenty-three trillion, three hundred four billion, one hundred forty million, four hundred forty-three thousand, one hundred fifty-one".

Divisors: 1 25981 896968571 23304140443151