Base | Representation |
---|---|
bin | 10101101101011101… |
… | …010000101010000111 |
3 | 2020011121011211212121 |
4 | 111231131100222013 |
5 | 340220133122211 |
6 | 14413052230411 |
7 | 1453450062346 |
oct | 255535205207 |
9 | 66147154777 |
10 | 23311223431 |
11 | 998263a211 |
12 | 4626a6b407 |
13 | 22766b9642 |
14 | 11b1d83b5d |
15 | 9167d9271 |
hex | 56d750a87 |
23311223431 has 2 divisors, whose sum is σ = 23311223432. Its totient is φ = 23311223430.
The previous prime is 23311223423. The next prime is 23311223473. The reversal of 23311223431 is 13432211332.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23311223431 - 23 = 23311223423 is a prime.
It is a super-2 number, since 2×233112234312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 23311223396 and 23311223405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23311223401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11655611715 + 11655611716.
It is an arithmetic number, because the mean of its divisors is an integer number (11655611716).
Almost surely, 223311223431 is an apocalyptic number.
23311223431 is a deficient number, since it is larger than the sum of its proper divisors (1).
23311223431 is an equidigital number, since it uses as much as digits as its factorization.
23311223431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592, while the sum is 25.
Adding to 23311223431 its reverse (13432211332), we get a palindrome (36743434763).
The spelling of 23311223431 in words is "twenty-three billion, three hundred eleven million, two hundred twenty-three thousand, four hundred thirty-one".
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