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233113131281 is a prime number
BaseRepresentation
bin1101100100011010100…
…0000001100100010001
3211021201001111001011002
43121012220001210101
512304403430200111
6255031331231345
722561521631232
oct3310650014421
9737631431132
10233113131281
118a9543158a8
1239219148555
1318ca0659194
14b3d5b81089
1560e553c63b
hex3646a01911

233113131281 has 2 divisors, whose sum is σ = 233113131282. Its totient is φ = 233113131280.

The previous prime is 233113131271. The next prime is 233113131283. The reversal of 233113131281 is 182131311332.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 199823304256 + 33289827025 = 447016^2 + 182455^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-233113131281 is a prime.

It is a super-2 number, since 2×2331131312812 (a number of 24 digits) contains 22 as substring.

Together with 233113131283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (233113131283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116556565640 + 116556565641.

It is an arithmetic number, because the mean of its divisors is an integer number (116556565641).

Almost surely, 2233113131281 is an apocalyptic number.

It is an amenable number.

233113131281 is a deficient number, since it is larger than the sum of its proper divisors (1).

233113131281 is an equidigital number, since it uses as much as digits as its factorization.

233113131281 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2592, while the sum is 29.

The spelling of 233113131281 in words is "two hundred thirty-three billion, one hundred thirteen million, one hundred thirty-one thousand, two hundred eighty-one".