23312003000401 has 4 divisors (see below), whose sum is σ = 23360671065600. Its totient is φ = 23263334935204.

The previous prime is 23312003000371. The next prime is 23312003000471. The reversal of 23312003000401 is 10400030021332.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23312003000401 - 2¹⁵ = 23312002967633 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23312003000471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24334031881 + ... + 24334032838.

It is an arithmetic number, because the mean of its divisors is an integer number (5840167766400).

Almost surely, 2^{23312003000401} is an apocalyptic number.

It is an amenable number.

23312003000401 is a deficient number, since it is larger than the sum of its proper divisors (48668065199).

23312003000401 is an equidigital number, since it uses as much as digits as its factorization.

23312003000401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48668065198.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 23312003000401 its reverse (10400030021332), we get a palindrome (33712033021733).

The spelling of 23312003000401 in words is "twenty-three trillion, three hundred twelve billion, three million, four hundred one", and thus it is an aban number.