Base | Representation |
---|---|
bin | 110101000000010111110010… |
… | …110010000011000111000111 |
3 | 1010120102020122220211100212011 |
4 | 311000113302302003013013 |
5 | 221023432340330144312 |
6 | 2143450435133035051 |
7 | 100050336543535534 |
oct | 6500276262030707 |
9 | 1116366586740764 |
10 | 233122013131207 |
11 | 68309543a304a2 |
12 | 22190736625a87 |
13 | a010408509585 |
14 | 417d246725d8b |
15 | 1be408a16ada7 |
hex | d405f2c831c7 |
233122013131207 has 2 divisors, whose sum is σ = 233122013131208. Its totient is φ = 233122013131206.
The previous prime is 233122013131081. The next prime is 233122013131223. The reversal of 233122013131207 is 702131310221332.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 233122013131207 - 215 = 233122013098439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (233122013101207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116561006565603 + 116561006565604.
It is an arithmetic number, because the mean of its divisors is an integer number (116561006565604).
Almost surely, 2233122013131207 is an apocalyptic number.
233122013131207 is a deficient number, since it is larger than the sum of its proper divisors (1).
233122013131207 is an equidigital number, since it uses as much as digits as its factorization.
233122013131207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 233122013131207 its reverse (702131310221332), we get a palindrome (935253323352539).
The spelling of 233122013131207 in words is "two hundred thirty-three trillion, one hundred twenty-two billion, thirteen million, one hundred thirty-one thousand, two hundred seven".
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