Base | Representation |
---|---|
bin | 10101101101100100… |
… | …100010001010000101 |
3 | 2020011201202201100121 |
4 | 111231210202022011 |
5 | 340221130130432 |
6 | 14413201141541 |
7 | 1453502223244 |
oct | 255544421205 |
9 | 66151681317 |
10 | 23313130117 |
11 | 9983721792 |
12 | 462762a8b1 |
13 | 2276c06464 |
14 | 11b231c95b |
15 | 916a64197 |
hex | 56d922285 |
23313130117 has 2 divisors, whose sum is σ = 23313130118. Its totient is φ = 23313130116.
The previous prime is 23313130109. The next prime is 23313130133. The reversal of 23313130117 is 71103131332.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20173657156 + 3139472961 = 142034^2 + 56031^2 .
It is a cyclic number.
It is not a de Polignac number, because 23313130117 - 23 = 23313130109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23313130091 and 23313130100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23313137117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11656565058 + 11656565059.
It is an arithmetic number, because the mean of its divisors is an integer number (11656565059).
Almost surely, 223313130117 is an apocalyptic number.
It is an amenable number.
23313130117 is a deficient number, since it is larger than the sum of its proper divisors (1).
23313130117 is an equidigital number, since it uses as much as digits as its factorization.
23313130117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 23313130117 its reverse (71103131332), we get a palindrome (94416261449).
The spelling of 23313130117 in words is "twenty-three billion, three hundred thirteen million, one hundred thirty thousand, one hundred seventeen".
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