Search a number
-
+
2331314401081 is a prime number
BaseRepresentation
bin100001111011001101001…
…010101010111100111001
322020212112022100021101211
4201323031022222330321
5301144012441313311
64542554022243121
7330301100306401
oct41731512527471
98225468307354
102331314401081
118197832250a6
123179a85864a1
1313bac3b65b93
1480b9c829801
154099989c821
hex21ecd2aaf39

2331314401081 has 2 divisors, whose sum is σ = 2331314401082. Its totient is φ = 2331314401080.

The previous prime is 2331314401027. The next prime is 2331314401121. The reversal of 2331314401081 is 1801044131332.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1928196074025 + 403118327056 = 1388595^2 + 634916^2 .

It is a cyclic number.

It is not a de Polignac number, because 2331314401081 - 231 = 2329166917433 is a prime.

It is a super-2 number, since 2×23313144010812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2331314405081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1165657200540 + 1165657200541.

It is an arithmetic number, because the mean of its divisors is an integer number (1165657200541).

Almost surely, 22331314401081 is an apocalyptic number.

It is an amenable number.

2331314401081 is a deficient number, since it is larger than the sum of its proper divisors (1).

2331314401081 is an equidigital number, since it uses as much as digits as its factorization.

2331314401081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

The spelling of 2331314401081 in words is "two trillion, three hundred thirty-one billion, three hundred fourteen million, four hundred one thousand, eighty-one".