Base | Representation |
---|---|
bin | 1010100110100000111010… |
… | …10111101011010100011101 |
3 | 10001112202102010211212202011 |
4 | 11103100131113223110131 |
5 | 11023432200224304301 |
6 | 121330035243031221 |
7 | 4624231061524522 |
oct | 523203527532435 |
9 | 101482363755664 |
10 | 23313575228701 |
11 | 747926048428a |
12 | 27463b120b511 |
13 | 10015cb248a34 |
14 | 5a855119b149 |
15 | 2a668d963a51 |
hex | 15341d5eb51d |
23313575228701 has 2 divisors, whose sum is σ = 23313575228702. Its totient is φ = 23313575228700.
The previous prime is 23313575228659. The next prime is 23313575228767. The reversal of 23313575228701 is 10782257531332.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23044656235225 + 268918993476 = 4800485^2 + 518574^2 .
It is a cyclic number.
It is not a de Polignac number, because 23313575228701 - 29 = 23313575228189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23313575228101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11656787614350 + 11656787614351.
It is an arithmetic number, because the mean of its divisors is an integer number (11656787614351).
Almost surely, 223313575228701 is an apocalyptic number.
It is an amenable number.
23313575228701 is a deficient number, since it is larger than the sum of its proper divisors (1).
23313575228701 is an equidigital number, since it uses as much as digits as its factorization.
23313575228701 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2116800, while the sum is 49.
The spelling of 23313575228701 in words is "twenty-three trillion, three hundred thirteen billion, five hundred seventy-five million, two hundred twenty-eight thousand, seven hundred one".
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