Search a number
-
+
2332505141131 = 11607349334303
BaseRepresentation
bin100001111100010100001…
…000111110111110001011
322020222121021221010200011
4201330110020332332023
5301203432304004011
64543312120052351
7330342436366624
oct41742410767613
98228537833604
102332505141131
1181a234386790
1231807b3040b7
1313bc537675a9
1480c72a28a4b
1540a191a9621
hex21f1423ef8b

2332505141131 has 8 divisors (see below), whose sum is σ = 2548743081984. Its totient is φ = 2116965870120.

The previous prime is 2332505141119. The next prime is 2332505141147. The reversal of 2332505141131 is 1311415052332.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2332505141131 - 27 = 2332505141003 is a prime.

It is a super-2 number, since 2×23325051411312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2332505141093 and 2332505141102.

It is not an unprimeable number, because it can be changed into a prime (2332505141171) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 174660475 + ... + 174673828.

It is an arithmetic number, because the mean of its divisors is an integer number (318592885248).

Almost surely, 22332505141131 is an apocalyptic number.

2332505141131 is a deficient number, since it is larger than the sum of its proper divisors (216237940853).

2332505141131 is a wasteful number, since it uses less digits than its factorization.

2332505141131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 349334921.

The product of its (nonzero) digits is 10800, while the sum is 31.

The spelling of 2332505141131 in words is "two trillion, three hundred thirty-two billion, five hundred five million, one hundred forty-one thousand, one hundred thirty-one".

Divisors: 1 11 607 6677 349334303 3842677333 212045921921 2332505141131