Search a number
-
+
23325341441 is a prime number
BaseRepresentation
bin10101101110010011…
…000111011100000001
32020012120202010010212
4111232103013130001
5340232241411231
614414315003505
71454011062623
oct255623073401
966176663125
1023325341441
11998a602296
12462b739595
1322795c06ac
1411b3bbac13
15917b7742b
hex56e4c7701

23325341441 has 2 divisors, whose sum is σ = 23325341442. Its totient is φ = 23325341440.

The previous prime is 23325341437. The next prime is 23325341449. The reversal of 23325341441 is 14414352332.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23201687041 + 123654400 = 152321^2 + 11120^2 .

It is a cyclic number.

It is not a de Polignac number, because 23325341441 - 22 = 23325341437 is a prime.

It is a super-3 number, since 3×233253414413 (a number of 32 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23325341398 and 23325341407.

It is not a weakly prime, because it can be changed into another prime (23325341449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11662670720 + 11662670721.

It is an arithmetic number, because the mean of its divisors is an integer number (11662670721).

Almost surely, 223325341441 is an apocalyptic number.

It is an amenable number.

23325341441 is a deficient number, since it is larger than the sum of its proper divisors (1).

23325341441 is an equidigital number, since it uses as much as digits as its factorization.

23325341441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34560, while the sum is 32.

Adding to 23325341441 its reverse (14414352332), we get a palindrome (37739693773).

The spelling of 23325341441 in words is "twenty-three billion, three hundred twenty-five million, three hundred forty-one thousand, four hundred forty-one".