Base | Representation |
---|---|
bin | 1010100111000001101001… |
… | …00011101011011011101111 |
3 | 10001121102202112211000212122 |
4 | 11103200310203223123233 |
5 | 11024224140343320142 |
6 | 121342102445223155 |
7 | 4625422333611221 |
oct | 523406443533357 |
9 | 101542675730778 |
10 | 23331144120047 |
11 | 74857566833a5 |
12 | 2749894b61abb |
13 | 100316b06522a |
14 | 5a933a646411 |
15 | 2a6d6b0611d2 |
hex | 1538348eb6ef |
23331144120047 has 2 divisors, whose sum is σ = 23331144120048. Its totient is φ = 23331144120046.
The previous prime is 23331144120023. The next prime is 23331144120113. The reversal of 23331144120047 is 74002144113332.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23331144120047 - 28 = 23331144119791 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23331144119989 and 23331144120016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23331144120017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11665572060023 + 11665572060024.
It is an arithmetic number, because the mean of its divisors is an integer number (11665572060024).
Almost surely, 223331144120047 is an apocalyptic number.
23331144120047 is a deficient number, since it is larger than the sum of its proper divisors (1).
23331144120047 is an equidigital number, since it uses as much as digits as its factorization.
23331144120047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 23331144120047 its reverse (74002144113332), we get a palindrome (97333288233379).
The spelling of 23331144120047 in words is "twenty-three trillion, three hundred thirty-one billion, one hundred forty-four million, one hundred twenty thousand, forty-seven".
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