Search a number
-
+
23333212131973 is a prime number
BaseRepresentation
bin1010100111000101011111…
…10100100001001010000101
310001121122002200010220220221
411103202233310201022011
511024242404301210343
6121343044002024341
74625524514456422
oct523425764411205
9101548080126827
1023333212131973
117486617a53367
12274a1716480b1
13100340a633223
145a9495166d49
152a6e3c8aa5ed
hex1538afd21285

23333212131973 has 2 divisors, whose sum is σ = 23333212131974. Its totient is φ = 23333212131972.

The previous prime is 23333212131953. The next prime is 23333212132033. The reversal of 23333212131973 is 37913121233332.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23017944480804 + 315267651169 = 4797702^2 + 561487^2 .

It is a cyclic number.

It is not a de Polignac number, because 23333212131973 - 241 = 21134188876421 is a prime.

It is a super-4 number, since 4×233332121319734 (a number of 55 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23333212131913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11666606065986 + 11666606065987.

It is an arithmetic number, because the mean of its divisors is an integer number (11666606065987).

Almost surely, 223333212131973 is an apocalyptic number.

It is an amenable number.

23333212131973 is a deficient number, since it is larger than the sum of its proper divisors (1).

23333212131973 is an equidigital number, since it uses as much as digits as its factorization.

23333212131973 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 367416, while the sum is 43.

The spelling of 23333212131973 in words is "twenty-three trillion, three hundred thirty-three billion, two hundred twelve million, one hundred thirty-one thousand, nine hundred seventy-three".