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23341444041053 is a prime number
BaseRepresentation
bin1010100111010100110100…
…11110110000100101011101
310001122102100100221020021102
411103222122132300211131
511024411234133303203
6121350524504242445
74626235512523355
oct523523236604535
9101572310836242
1023341444041053
11748a061718506
12274b88a470425
13100411cc23548
145a9a3655bb65
152a7270414888
hex153a9a7b095d

23341444041053 has 2 divisors, whose sum is σ = 23341444041054. Its totient is φ = 23341444041052.

The previous prime is 23341444040987. The next prime is 23341444041061. The reversal of 23341444041053 is 35014044414332.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20676054750649 + 2665389290404 = 4547093^2 + 1632602^2 .

It is a cyclic number.

It is not a de Polignac number, because 23341444041053 - 218 = 23341443778909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23341444040998 and 23341444041016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23341444061053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11670722020526 + 11670722020527.

It is an arithmetic number, because the mean of its divisors is an integer number (11670722020527).

Almost surely, 223341444041053 is an apocalyptic number.

It is an amenable number.

23341444041053 is a deficient number, since it is larger than the sum of its proper divisors (1).

23341444041053 is an equidigital number, since it uses as much as digits as its factorization.

23341444041053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 276480, while the sum is 38.

Adding to 23341444041053 its reverse (35014044414332), we get a palindrome (58355488455385).

The spelling of 23341444041053 in words is "twenty-three trillion, three hundred forty-one billion, four hundred forty-four million, forty-one thousand, fifty-three".