Base | Representation |
---|---|
bin | 1010100111111111001001… |
… | …01101000010111001011101 |
3 | 10001201120222202210200001111 |
4 | 11103333210231002321131 |
5 | 11030244302004332131 |
6 | 121405203202542021 |
7 | 4631001524250664 |
oct | 523774455027135 |
9 | 101646882720044 |
10 | 23364164136541 |
11 | 7498760609528 |
12 | 275416b367911 |
13 | 1006300ccc627 |
14 | 5aab8dbc7ddb |
15 | 2a7b4ed84ab1 |
hex | 153fe4b42e5d |
23364164136541 has 2 divisors, whose sum is σ = 23364164136542. Its totient is φ = 23364164136540.
The previous prime is 23364164136517. The next prime is 23364164136553. The reversal of 23364164136541 is 14563146146332.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21323809008441 + 2040355128100 = 4617771^2 + 1428410^2 .
It is a cyclic number.
It is not a de Polignac number, because 23364164136541 - 219 = 23364163612253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23364164136041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11682082068270 + 11682082068271.
It is an arithmetic number, because the mean of its divisors is an integer number (11682082068271).
Almost surely, 223364164136541 is an apocalyptic number.
It is an amenable number.
23364164136541 is a deficient number, since it is larger than the sum of its proper divisors (1).
23364164136541 is an equidigital number, since it uses as much as digits as its factorization.
23364164136541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3732480, while the sum is 49.
The spelling of 23364164136541 in words is "twenty-three trillion, three hundred sixty-four billion, one hundred sixty-four million, one hundred thirty-six thousand, five hundred forty-one".
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