Base | Representation |
---|---|
bin | 100010000011010100101… |
… | …010011110011010010111 |
3 | 22021201000201111100001221 |
4 | 202003110222132122113 |
5 | 301314340202112211 |
6 | 4550554530231211 |
7 | 331030061531443 |
oct | 42032452363227 |
9 | 8251021440057 |
10 | 2340030113431 |
11 | 822445aa385a |
12 | 31961b425507 |
13 | 13c88275a01a |
14 | 8138819b823 |
15 | 40d09b20c71 |
hex | 220d4a9e697 |
2340030113431 has 2 divisors, whose sum is σ = 2340030113432. Its totient is φ = 2340030113430.
The previous prime is 2340030113359. The next prime is 2340030113437. The reversal of 2340030113431 is 1343110300432.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2340030113431 - 29 = 2340030112919 is a prime.
It is a super-2 number, since 2×23400301134312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2340030113396 and 2340030113405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2340030113437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170015056715 + 1170015056716.
It is an arithmetic number, because the mean of its divisors is an integer number (1170015056716).
Almost surely, 22340030113431 is an apocalyptic number.
2340030113431 is a deficient number, since it is larger than the sum of its proper divisors (1).
2340030113431 is an equidigital number, since it uses as much as digits as its factorization.
2340030113431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 2340030113431 its reverse (1343110300432), we get a palindrome (3683140413863).
The spelling of 2340030113431 in words is "two trillion, three hundred forty billion, thirty million, one hundred thirteen thousand, four hundred thirty-one".
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