Base | Representation |
---|---|
bin | 1010101001000011110001… |
… | …00100000000011001101011 |
3 | 10001212010002020111201210202 |
4 | 11110201320210000121223 |
5 | 11031400224130031410 |
6 | 121434134552302415 |
7 | 4633444464411461 |
oct | 524417044003153 |
9 | 101763066451722 |
10 | 23401004533355 |
11 | 7502345aa5969 |
12 | 275b3310a1a0b |
13 | 10099225b86b7 |
14 | 5ac8868c4831 |
15 | 2a8aa929cca5 |
hex | 15487890066b |
23401004533355 has 8 divisors (see below), whose sum is σ = 29559163621200. Its totient is φ = 17735498172576.
The previous prime is 23401004533343. The next prime is 23401004533363. The reversal of 23401004533355 is 55333540010432.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 23401004533355 - 210 = 23401004532331 is a prime.
It is a super-2 number, since 2×234010045333552 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 123163181660 + ... + 123163181849.
It is an arithmetic number, because the mean of its divisors is an integer number (3694895452650).
Almost surely, 223401004533355 is an apocalyptic number.
23401004533355 is a deficient number, since it is larger than the sum of its proper divisors (6158159087845).
23401004533355 is a wasteful number, since it uses less digits than its factorization.
23401004533355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 246326363533.
The product of its (nonzero) digits is 324000, while the sum is 38.
Adding to 23401004533355 its reverse (55333540010432), we get a palindrome (78734544543787).
The spelling of 23401004533355 in words is "twenty-three trillion, four hundred one billion, four million, five hundred thirty-three thousand, three hundred fifty-five".
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