Base | Representation |
---|---|
bin | 1101100111110001011… |
… | …0000101111001111001 |
3 | 211101000212101020120111 |
4 | 3121330112011321321 |
5 | 12313230141300441 |
6 | 255301004424321 |
7 | 22623044403205 |
oct | 3317426057171 |
9 | 741025336514 |
10 | 234014400121 |
11 | 90277034487 |
12 | 3942ab480a1 |
13 | 190b52a8258 |
14 | b47d74bb05 |
15 | 614971a081 |
hex | 367c585e79 |
234014400121 has 2 divisors, whose sum is σ = 234014400122. Its totient is φ = 234014400120.
The previous prime is 234014400091. The next prime is 234014400131. The reversal of 234014400121 is 121004410432.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 197202605625 + 36811794496 = 444075^2 + 191864^2 .
It is a cyclic number.
It is not a de Polignac number, because 234014400121 - 213 = 234014391929 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 234014400092 and 234014400101.
It is not a weakly prime, because it can be changed into another prime (234014400131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117007200060 + 117007200061.
It is an arithmetic number, because the mean of its divisors is an integer number (117007200061).
Almost surely, 2234014400121 is an apocalyptic number.
It is an amenable number.
234014400121 is a deficient number, since it is larger than the sum of its proper divisors (1).
234014400121 is an equidigital number, since it uses as much as digits as its factorization.
234014400121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 234014400121 its reverse (121004410432), we get a palindrome (355018810553).
The spelling of 234014400121 in words is "two hundred thirty-four billion, fourteen million, four hundred thousand, one hundred twenty-one".
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