234014410433 has 4 divisors (see below), whose sum is σ = 236976618240. Its totient is φ = 231052202628.

The previous prime is 234014410403. The next prime is 234014410451. The reversal of 234014410433 is 334014410432.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 234014410433 - 2¹² = 234014406337 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 234014410396 and 234014410405.

It is not an unprimeable number, because it can be changed into a prime (234014410403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1481103785 + ... + 1481103942.

It is an arithmetic number, because the mean of its divisors is an integer number (59244154560).

Almost surely, 2^234014410433 is an apocalyptic number.

It is an amenable number.

234014410433 is a deficient number, since it is larger than the sum of its proper divisors (2962207807).

234014410433 is an equidigital number, since it uses as much as digits as its factorization.

234014410433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2962207806.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 234014410433 its reverse (334014410432), we get a palindrome (568028820865).

Subtracting 234014410433 from its reverse (334014410432), we obtain a palindrome (99999999999).

The spelling of 234014410433 in words is "two hundred thirty-four billion, fourteen million, four hundred ten thousand, four hundred thirty-three".