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234020133111 = 31743106712327
BaseRepresentation
bin1101100111110010101…
…1111101100011110111
3211101001021011111202110
43121330223331203313
512313233123224421
6255301331342103
722623144211362
oct3317453754367
9741037144673
10234020133111
119027a29a796
1239430a51933
13190b653485b
14b4804010d9
156149e9da76
hex367cafd8f7

234020133111 has 16 divisors (see below), whose sum is σ = 338064655104. Its totient is φ = 143421366144.

The previous prime is 234020133103. The next prime is 234020133119. The reversal of 234020133111 is 111331020432.

It is an interprime number because it is at equal distance from previous prime (234020133103) and next prime (234020133119).

It is not a de Polignac number, because 234020133111 - 23 = 234020133103 is a prime.

It is a super-3 number, since 3×2340201331113 (a number of 35 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (234020133119) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53353971 + ... + 53358356.

It is an arithmetic number, because the mean of its divisors is an integer number (21129040944).

Almost surely, 2234020133111 is an apocalyptic number.

234020133111 is a deficient number, since it is larger than the sum of its proper divisors (104044521993).

234020133111 is a wasteful number, since it uses less digits than its factorization.

234020133111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106712390.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 234020133111 its reverse (111331020432), we get a palindrome (345351153543).

The spelling of 234020133111 in words is "two hundred thirty-four billion, twenty million, one hundred thirty-three thousand, one hundred eleven".

Divisors: 1 3 17 43 51 129 731 2193 106712327 320136981 1814109559 4588630061 5442328677 13765890183 78006711037 234020133111