Base | Representation |
---|---|
bin | 100010000011101011011… |
… | …011110000111011111001 |
3 | 22021202000100022221120001 |
4 | 202003223123300323321 |
5 | 301321131001224423 |
6 | 4551100454233001 |
7 | 331042410615445 |
oct | 42035333607371 |
9 | 8252010287501 |
10 | 2340412133113 |
11 | 8226216a88aa |
12 | 319707355761 |
13 | 13c913944582 |
14 | 813c2c01825 |
15 | 40d2d431cad |
hex | 220eb6f0ef9 |
2340412133113 has 2 divisors, whose sum is σ = 2340412133114. Its totient is φ = 2340412133112.
The previous prime is 2340412133089. The next prime is 2340412133117. The reversal of 2340412133113 is 3113312140432.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1372053794409 + 968358338704 = 1171347^2 + 984052^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2340412133113 is a prime.
It is not a weakly prime, because it can be changed into another prime (2340412133117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170206066556 + 1170206066557.
It is an arithmetic number, because the mean of its divisors is an integer number (1170206066557).
Almost surely, 22340412133113 is an apocalyptic number.
It is an amenable number.
2340412133113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2340412133113 is an equidigital number, since it uses as much as digits as its factorization.
2340412133113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 2340412133113 its reverse (3113312140432), we get a palindrome (5453724273545).
The spelling of 2340412133113 in words is "two trillion, three hundred forty billion, four hundred twelve million, one hundred thirty-three thousand, one hundred thirteen".
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