2340433 has 4 divisors (see below), whose sum is σ = 2366820. Its totient is φ = 2314048.

The previous prime is 2340431. The next prime is 2340451. The reversal of 2340433 is 3340432.

2340433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 760384 + 1580049 = 872^2 + 1257^2 .

It is a cyclic number.

It is not a de Polignac number, because 2340433 - 2¹ = 2340431 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2340433.

It is not an unprimeable number, because it can be changed into a prime (2340431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13060 + ... + 13237.

It is an arithmetic number, because the mean of its divisors is an integer number (591705).

2^2340433 is an apocalyptic number.

It is an amenable number.

2340433 is a deficient number, since it is larger than the sum of its proper divisors (26387).

2340433 is an equidigital number, since it uses as much as digits as its factorization.

2340433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26386.

The product of its (nonzero) digits is 864, while the sum is 19.

The square root of 2340433 is about 1529.8473780087. The cubic root of 2340433 is about 132.7696277678.

Adding to 2340433 its reverse (3340432), we get a palindrome (5680865).

Subtracting 2340433 from its reverse (3340432), we obtain a palindrome (999999).

The spelling of 2340433 in words is "two million, three hundred forty thousand, four hundred thirty-three".